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  • 🚀 Daily Digest: AI and Web Dev: Unlocking CSS, SQL Optimization, and the Future of Decentralized AI

🚀 Daily Digest: AI and Web Dev: Unlocking CSS, SQL Optimization, and the Future of Decentralized AI

PLUS: Explore AI-Powered Penetration Testing, Real-Time Generative UI, and More in Today’s Coding Toolbox

Daily Issue #29

🎆 NEWS, INNOVATIONS, TRENDS, TUTORIALS

🧰 CODING TOOLBOX

  • PentestGPT - AI-Powered Automated Penetration Testing Tool

  • hydraai - a dev tool for generative UI that adapts to user context in real-time

  • griptape - Modular Python framework for AI agents and workflows with chain-of-thought reasoning, tools, and memory

  • HivisionIDPhotos - a lightweight and efficient AI ID photos tools

  • julep - Open-source alternative to Assistant's API with a managed backend for memory, RAG, tools and tasks

#️⃣ DO YOU AI PROMPT?

Scientific Data Visualizer

I want you to act as a scientific data visualizer. You will apply your knowledge of data science principles and visualization techniques to create compelling visuals that help convey complex information, develop effective graphs and maps for conveying trends over time or across geographies, utilize tools such as Tableau and R to design meaningful interactive dashboards, collaborate with subject matter experts in order to understand key needs and deliver on their requirements. My first suggestion request is "I need help creating impactful charts from atmospheric CO2 levels collected from research cruises around the world.

💻 CODE SNIPPET OF THE DAY

Optimizing Fetch Requests with a Vanilla JavaScript Debounce Function (No Lodash Required)

Problem: I needed to find a way to check if two arrays have no elements in common. After some research, I discovered that JavaScript provides a native method to handle this efficiently.

Solution: Use Set.prototype.isDisjointWith() to check if two sets (derived from arrays) have no common elements.

const setA = new Set([1, 2]);
const setB = new Set([3, 4]);
console.log(setA.isDisjointWith(setB)); // Output: true

Keywords: JavaScript disjoint sets, checking array intersection, isDisjointWith method, no common elements in arrays, set operations in JavaScript, array comparison.

🛠️ SUGGEST A TOOL

If you have built anything that you’d like to share with the community, get with me on X @dailysandbox_ 😀 

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